576v^2+48v+1=0

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Solution for 576v^2+48v+1=0 equation: 



576v^2+48v+1=0

a = 576; b = 48; c = +1;
Δ = b2-4ac
Δ = 482-4·576·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-48}{1152}=-1/24$

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